(28x-4x^2)/(32x+12)

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Solution for (28x-4x^2)/(32x+12) equation: 


D( x )

32*x+12 = 0

32*x+12 = 0

32*x+12 = 0

32*x+12 = 0 // - 12

32*x = -12 // : 32

x = -12/32

x = -3/8

x in (-oo:-3/8) U (-3/8:+oo)

(28*x-(4*x^2))/(32*x+12) = 0

(28*x-4*x^2)/(32*x+12) = 0

28*x-4*x^2 = 0

4*x*(7-x) = 0

7-x = 0 // - 7

-x = -7 // * -1

x = 7

4*x*(x-7) = 0

(4*x*(x-7))/(32*x+12) = 0

( 4*x )

4*x = 0 // : 4

x = 0

( x-7 )

x-7 = 0 // + 7

x = 7

x in { 0, 7 }

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